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Answers
Example 1:-
F = xy + x’y + xy’
From Theorem T1
= xy + xy + x’y + xy’
= y(x + x’) + x(y + y’)
From Postulate P3
Example 2:-
F = x + x’y
From Postulate P8
= (x + x’)(x + y)
From Postulate P3
F = x + y
Example 3:-
F = (x + y)(x +y’)
From Postulate P8
= x + yy’
From Postulate P4
= x
Example 4:-
F = xy + x’z + yz
From Postulate P3
= xy + x’z + xyz + x’yz
= xy(1 + z) + x’z(1 + y)
= xy + x’z
Example 5:-
F = xyz + x’y + xyz’
= xyz + x’yz + x’yz’ + xyz’
= yz + yz’
= y
Simplify following Boolean Functions:
Exercise :-
1. F = xy + x’y + xy’
2. F = x + x’y
3. F = (x + y)(x +y’)
4. F = xy + x’z + yz
5. F = xyz + x’y + xyz’
= y + x