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Answers

Example 1:-

F = xy + x’y + xy’

From Theorem T1

= xy + xy + x’y + xy’

= y(x + x’) + x(y + y’)

From Postulate P3

Example 2:-

F = x + x’y

From Postulate P8

= (x + x’)(x + y)

From Postulate P3

F = x + y

Example 3:-

F = (x + y)(x +y’)

From Postulate P8

= x + yy’

From Postulate P4

= x

Example 4:-

F = xy + x’z + yz

From Postulate P3

= xy + x’z + xyz + x’yz

= xy(1 + z) + x’z(1 + y)

= xy + x’z

Example 5:-

F = xyz + x’y + xyz’

= xyz + x’yz + x’yz’ + xyz’

= yz + yz’

= y

Simplify following Boolean Functions:

Exercise :-

1. F = xy + x’y + xy’

2. F = x + x’y

3. F = (x + y)(x +y’)

4. F = xy + x’z + yz

5. F = xyz + x’y + xyz’

= y + x